Question

.The Pythagorean triples whose smallest number is 8: *

Answer 1

Step-by-step explanation:

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Pythagoras triplets are of the form.

2m, m² -1 and m² + 1.

It is given that smallest number is 8.

So, 2m = 8.

m = 4.

Now, second number = m² -1 = 4² - 1 = 15.

and, third number = m² + 1 = 4² + 1 = 17.

Hence, the triplet is 8, 15 and 17.

Verification :-

17² = 8² + 15²

289 = 64 + 225

289 = 289.

Hence, proved.

Hope It Helps

Suhana17

Suhana17

2m= 8/2

= 4

4×4 = 16

16+1= 17

16-1=15

therefore the triplets are 8,17,15