The quadrant polynomial the sum and producet zero -1 , 20 respectly .also find zero of the polynomial
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let the zeroes are a and b
ATQ, a+b=-1
and ab=20
the required polynomial is
k[x²-(a+b)x+(ab)]
k[x²-(-1)x+(20)]
k[x²+1x+20]
k[x²+x+20]
so the polynomial is x²+x+20
now, in x²+x+20, a=1; b=1 ; c=20
D=b²-4ac=1²-4*20=1-80=-79
here, D<0. So the polynomial has no real roots
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