Question

The quadratic equation 2x² - 13x + 1 = 0 has:
To distinct roots​

Answer 1

Explanation:

A quadratic equation, ax^2 + bx + c = 0 ; a ≠ 0 will have two distinct real roots if its discriminant, D = b^2 - 4ac > 0.

Given equation is 2x^2 - 13x + 1 = 0.

On comparing with standard equation we have,

⇒ a = 2 , b = -13 , c = 1

Now,

⇒ D = b^2 - 4ac

⇒ D = (-13)^2 - 4 × 2 × 1

⇒ D = 169 - 8

⇒ D = 161 > 0

Hence, the equation 2x^2 - 13x + 1 = 0 has two distinct real roots.