the quadratic equation 6 X + 2 Y =3 and kX + Y =2 has unique solution find the value of k
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Answered by
4
6x +2y=3
kx+y=2
a1/a2=b1/b2 not equal to c1/c2
6/k=2/1
6/k=2
k=3
6/k not = 3/2
k not equal to 4
therefore it is proved that k=3 where k not= 4
kx+y=2
a1/a2=b1/b2 not equal to c1/c2
6/k=2/1
6/k=2
k=3
6/k not = 3/2
k not equal to 4
therefore it is proved that k=3 where k not= 4
Answered by
4
6x+2y=3
2kx+2y=4
2k=6 the equations has no solution
That is, if k=3 the equations has no solution.
2kx+2y=4
2k=6 the equations has no solution
That is, if k=3 the equations has no solution.
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