The quadratic equation for which the sum of the roots is 12 and the sum of the cubes of the roots
is 468.
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Answer:Let α,β be roots of equation
α+β=3
α
3
+β
3
=63
α
3
+β
3
=(α+β)
3
−3αβ(α+β)
6
3
=(3)
3
−3αβ(3)
63=27−9αβ
9αβ=−36
αβ=−4
∴ equation
x
2
−3x+(−4)=0
Step-by-step explanation:
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