The quadratic equation ..... has 3 as one of its roots,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) x²–X–6=0
(b) x²+x-6=0
(c) x²-x+6=0
(d) x²+x+6=0
Answers
Answered by
3
It's option A
Hope this helps you...
Hope this helps you...
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Answered by
4
Option ( a ) is correct.
Explanation :
Put x = 3 in equation x² - x - 6 = 0
=> 3² - 3 - 6 = 0
=> 9 - 3 - 6 = 0
=> 9 - 9 = 0
=> 0 = 0 [ True ]
Therefore ,
x = 3 is one root of x² - x - 6 = 0
••••
Explanation :
Put x = 3 in equation x² - x - 6 = 0
=> 3² - 3 - 6 = 0
=> 9 - 3 - 6 = 0
=> 9 - 9 = 0
=> 0 = 0 [ True ]
Therefore ,
x = 3 is one root of x² - x - 6 = 0
••••
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