Question

The quadratic equaTion having roots (3+2√3 ) and 3+2√3

Answer 1

Step-by-step explanation:

equation is

x²+sum(x)+product

=x²+2(3+2√3)x+(3+2√3)²

here is ur answer

Answer 2

Answer:

x^2  -  2(3+2√3 ) + (3+2√3 )^2

Step-by-step explanation:

for quadratic equation ax^2 + bx +c =0

sum of roots = =b/a

product of roots = c/a

if = a=1

b=  -2(3+2√3 )

c = (3+2√3 )^2

Equation will be  

x^2  -  2(3+2√3 ) + (3+2√3 )^2