Question

The quadratic equation mx^2 -2root 5 mx + 15 =0 has two equal roots.

Answer 1

Answer:

76

Step-by-step explanation:

Abhishekbwjshehsueb

Answer 2

Answer:

The value of m is 3

Step-by-step explanation:

$mx^{2}-2\sqrt{5}mx+15 =0 \\D= b^{2}-4ac\\compare with ax^{2} +bx+c=0 we get a = m, b= - 2\sqrt{5}m , c= 15\\D= (-2\sqrt{5}m)^{2} - 4*m* 15\\= 20 m^{2} - 60m \\Roots are equal then \\20m^{2}-60m =0\\=> 20m= 60\\=>m=3$