the quadratic equation whise roots are sin 18° cos 36°
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Answered by
1
Answer:
16x2 – 12x + 1 = 0
It is given that sin2 18o and cos2 36o are the roots of the equation.
Step-by-step explanation:
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Answered by
0
Answer:
16x2 – 12x + 1 = 0
Step-by-step explanation:
It is given that sin2 18o and cos2 36o are the roots of the equation.
x2 – (sin2 18o + cos2 36o) x (sin2 18o + cos2 36o) x + (sin2 18o * cos2 36o) = 0
x2 – {[(√5 – 1) / 4]2 + [(√5 + 1) / 4]2} x + {[(√5 – 1) / 4] + [(√5 + 1) / 4]}2 = 0
x2 – 2 [(√5 / 4)2 + (1 / 4)2] x + (1 / 4)2 = 0
x2 – 2 (6 / 16) x + (1 / 16) = 0
16x2 – 12x + 1 = 0
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