the quadratic equation who roots are 2+√5 and 2-√5
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Step-by-step explanation:
According to the question,
Roots of quadratic equation are 2 + √5 and 2 - √5
Let α = 2 + √5
ß = 2 - √5
Sum of zeros of polynomial = α + ß
= 2 + √5 + 2 - √5
= 2 + 2
= 4
Product of zeros of polynomial = αß
= (2 + √5)(2 - √5)
= 4 - 5
= -1
Quadratic polynomial = k(x² - (α + ß)x + αß)
=> k(x² - 4x - 1)
'k' is constant.
Hope this helps....:)
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