Question

the quadratic equation whose one irrational root is (3+root 2)​

Answer 1

Answer:

one of the root is 3+√2and -3+√2

Step-by-step explanation:

i think it is the correct answer

Answer 2

Answer:

x^{2} -6x+7=0

PLZ:

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Concept:

1)irrational roots always exist in pair

so,if 3+root 2 is a root then 3-root 2 must be a root of that quadratic equation.

2)if a and b are roots of a quadratic equation then the quadratic equation is

      $x^{2} -x(a+b)+ab=0$

Step-by-step explanation:

here,

a=3+root 2  b=3-root 2

a+b=6

ab=9-2=7

Hence,the quadratic equation is

$x^{2} -6x+7=0$