the quadratic equation whose one of the root is (3-√5) is what
Answers
Answered by
0
Step-by-step explanation:
one root = (3-√5)
other root = 3+√5
sum of roots = (3-√5) + (3+√5)
= 6
product of roots = (3-√5) (3+√5)
= (9)^2 -(√5)^2
= 18 - 5
13
general quadratic equation are
x^2-(sum of roots)x+product of roots = 0
x^2 - 6x + 13 = 0
Similar questions