Question

The quadratic equation whose one of the root is (3-V5) is
1. x2-6x+4
2. 3x2 +5x+2=0
3. x2-2x+7=0
7
4. 2x2+3x+5=0​

Answer 1

Step-by-step explanation:

One root =

2−

5

3+

5

(2+

5

)

(2+

5

)

=

4−5

6+3

5

+2

5

+5

=−(11+5

5

)=−11−5

5

Other root ⇒−11+5

5

Equation ⇒x

2

−(−11−5

5

−11+5

5

)x+(−11−5

5

)(−11+5

5

)=0

x

2

+22x+(121−125)=0

x

2

+22x−4=0