Question

The quadratic equation whose one rational root is 3 + √2 is

Answer 1

Answer:x^2 - 6x+ 7

Step-by-step explanation:

Rational roots always occur in pairs,

One root is 3 + √2, then 2nd root will be 3 -√2

S= 3 + √2+ 3 - √2= 6

P=(3 + √2) (3 -√2) = 3^2-(√2)^2= 9-2=7

So, quadratic equations will be

x^2 -Sx+ P

x^2 - 6x+ 7

Answer 2

Answer:

x²-6x+7

Step-by-step explanation:

Rational roots always occur in pairs,

One root is 3 + √2, then 2nd root will be 3 -√2

S= 3 + √2+ 3 - √2= 6

P=(3 + √2) (3 -√2) = 3²-(√2)²= 9-2=7

So, quadratic equations will be

x² -Sx+ P

x² - 6x+ 7

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