Question

The quadratic equation whose root are ± i √7 is
a. x2 +7
b. X2 - 7
C. X2 + x + 7=0
d. X2-X-7=0
e. X2-X+7=0​

Answer 1

2+6x−7=0

x2+6x+9−9−7=0

x2+3x+3x+9=+16

x(x+3)+3(x+3)=16

(x+3)(x+3)=16

(x+3) 2=±(4)2

x+3=±4

2×a×b=6x

2×x×b=6x(∵a=x)

b= 2x/6x

b=3

b 2=9

Taking square root on both sides,

(Half of the coefficient of x = 26

∴b=3)

If, x + 3 = 4 x +3 = - 4

x = 4 - 3 x = - 4 - 3

x = 1 x = - 7

∴ 1 and - 7 are the roots of x2+6x−7=0

hope it helps

regards,

legendry python gamer

thank you

Answer 2

Answer:

option (a)

x²-7 = 0

refer to the attachment