Question

The quadratic equation whose root is 2 and -3/2 is given by

Answer 1

Answer:

$α=2, \: β = \frac{( - 3)}{2} \\Quadratic \: equation \\ </p><p>=x²-(α+β)x+αβ \\ </p><p>=x²-(2 + \frac{( - 3)}{2} ) x+ (2)( \frac{ (- 3)}{2} ) \\ = {x}^{2} - (2 - \frac{3}{2} )x + ( - 3) \\ = {x}^{2} - ( \frac{4 - 3}{2} )x - 3 \\ = {x}^{2} - \frac{x}{2} - 3 \\ multiply \: each \: term \: by \: 2 \\ = (1 \times 2) {x}^{2} - \frac{x}{2} \times 2 - 3 \times 2 \\ = 2 {x}^{2} - x - 6$