Math, asked by 002PRADEEP200, 7 days ago

The quadratic equation whose roots are (2+√3) and (2-√3) is
(a) 2x² - 4x+1=0
(b) x²-4x+1=0
(c) x² - 6x +4-0
(d) None of these

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Answers

Answered by arnav9116
0

Answer:

d) none of these

Explanation:

Here, roots of quadratic equation are given.

let m=(2+√3) and n=(2-√3)

according to general formula of quadratic equation, it is of form x²-(m+n)x+(mn)

sum of zeroes=(2+√3)+(2-√3)

= 2+√3+2-√3

= 4

product of zeroes=(2+√3)(2-√3)

=(2)²-(√3)²

[Since,(a+b)(a-b)=a²-b²]

= 4-3

=1

therefore, the equation is x²-(4)x+1

=x²-4x+1

hence, option d) none of these is the correct answer.

Answered by saiyamanshul60ph38p2
0

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