Question

the quadratic equation whose roots are -3,-4is

Answer 1

Let the roots be 'a' and 'b'.
Therefore,(ab)=(12) and (a+B)=(-7)
Hence the required quadratic equation will be of the form x^2-(a+b)x+(ab)
Required equation is :( x^2+7x+12)

Answer 2

the quadratic equation whose roots are -3,-4 is

SOLUTION

$x = - 3 \\ = > x + 3\\ \\ x = - 4 \\ = > x + 4 \\ \\ now \: \\ (x + 3)(x + 4) \\ {x}^{2} + 4x + 3x + 12 \\ {x}^{2} + 7x + 12$


THANKS