Question

the quadratic equation whose roots are -3 and -11 .​

Answer 1

Formula - x²-(a+ß)x+aß

=> x²-(-3-11)x+(-11×-3) =0

=>x²+14x+33=0.

Answer - x²+14x+33=0.

Answer 2

Answer:

x^2 + 14x + 33 = 0

Step-by-step explanation:

Given that,

The roots of a quadratic equation are -3 and -11.

Now, to find the quadratic equation.

We know that,

A quadratic equation is given by,

x^2 -(sum of roots)x + (product of roots) = 0

So, we need to find,

=> Sum of roots = -3+(-11) = -3-11 = -14

=> Product of roots = (-3)(-11) = 33

Substituting the values,

Therefore, we will get,

The required quadratic equation as :

=> x^2 - (-14)x + 33 = 0

=> x^2 + 14x + 33 = 0

Hence, the required quadratic equation is x^2+14x+33= 0