Math, asked by mkeerthana970, 5 hours ago

the quadratic equation whose roots are a, 1/a is​

Answers

Answered by IRONMAN44
5

Answer:

eq = ax^{2} - (a^{2} +1)x +1

Step-by-step explanation:

lets roots be

x = a

y = 1/a

sum of roots : x+y=a + 1/a = a^2 +1 /a

product of roots: xy = 1

so eq = k(x^{2} - (x + y)x + xy)

          = k(x^{2} - (\frac{a^{2} +1 }{a})x + 1)

   multiplying with a:

             = ax^{2} - (a^{2} +1)x +1

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