Math, asked by VaishnaviS13, 6 months ago

The quadratic equation whose roots are real and equal is
a) x^2-2x-8=0
b) x^2-4x+4=0
c)3x^2-5x+2=0
d) x^2-2 root 2x - 6=0
Explanation also needed ​

Answers

Answered by Anonymous
1

Step-by-step explanation:

if roots are real and equal then b^2-4ac=0(discriminant)

a)4-(4*2*(-8))!=0

b)16-(4*2*4)!=0

c)25-(4*2*3)!=0

d)8-(4*-6)!=0

there is no anss

Answered by shimla9645
1

Answer:

all real numbers will be greater than and equal to 0

and second thing no value will be come in negative

now apply factorise method on options one by one

b^2-4ac

put value of a,b,c in this equation of options one by one

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