Question

The quadratic equation whose zeros are 2 and -2 is

Answer 1

Answer:

$\\ x^{2}- 4 =0$

Step-by-step explanation:

Let the first root be α = 2

let the second root be β = -2

therefore,

α + β = 2 + (-2) = 0

α.β = 2 x (-2) = -4

Thus.

we know the form of the quadratic Equation...!

$x^{2} -(\alpha+\beta )x+ \alpha.\beta =0$

Finally putting the values in it

x^2 - (0)x  + (-4) = 0

x^2 -4 = 0

Thus the equation becomes ...!

$\\ x^{2}- 4 =0$

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