The quadratic equation x^2-6x+a=0 and x^2-cx+6=0 have one root in common. the other roots of first and second equations are in the ratio 4:3 .then the common root is?
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Let the common root of the given quadratic equation be α the other of equation x2 –6x + a = 0 be β and for x2– cx + 6 = 0 be γ.
For x2 –6x + a = 0
For x2 – cx + 6 = 0
On dividing (2) by (3), we get
So, from (2), αβ = 8
and from (1) α + β = 6
⇒ β = 6 – α
⇒ α (6 – α) = 8
⇒ 6α – α2 = 8
⇒ α2 – 6α + 8 = 0
⇒ α2 – 4α – 2α + 8 = 0
⇒ (α – 4) (α – 2) = 0
⇒ α = 2, 4
So, α can be 2 or 4,
Hence the common root is 2
For x2 –6x + a = 0
For x2 – cx + 6 = 0
On dividing (2) by (3), we get
So, from (2), αβ = 8
and from (1) α + β = 6
⇒ β = 6 – α
⇒ α (6 – α) = 8
⇒ 6α – α2 = 8
⇒ α2 – 6α + 8 = 0
⇒ α2 – 4α – 2α + 8 = 0
⇒ (α – 4) (α – 2) = 0
⇒ α = 2, 4
So, α can be 2 or 4,
Hence the common root is 2
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38
Answer:
so common root is 2
Step-by-step explanation:
common root is 2
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