Question

the quadratic equation X square - 4 x + K is equal to zero a distinct real root if.........​

Answer 1

QUESTION :–

● The quadratic equation x² - 4 x + K = 0 have Distinct and Real root. Then find k.

ANSWER :–

$\\ { \bold { k \leqslant 4 }}$

EXPLANATION :–

GIVEN :–

• A quadratic equation => x² - 4x + k = 0.

• Quadratic equation have Distinct and Real root.

TO FIND :–

Value of 'k'

SOLUTION :–

• If the roots of a Quadratic equation are Real and Distinct then Discriminant will be-

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:{ \boxed { \huge { \bold { D \geqslant 0}}}}$

• We know that –

$\\ { \implies \bold { D = {b}^{2} - 4ac}}$

$\\ { \implies \bold { D = {(-4)}^{2} - 4(1)(k)}}$

$\\ { \implies \bold { D = 16 - 4k}}$

But we know that –

$\\ { \implies { \bold { D \geqslant 0}}}$

$\\ { \implies \bold { 16 - 4k \geqslant 0 }}$

$\\ { \implies \bold { 16 \geqslant 4k }}$

$\\ { \implies \bold { 4k \leqslant 16 }}$

$\\ { \implies \bold { k \leqslant 4 }}$

Answer 2

Answer:

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