Question

the quadratic equation x2+2(k+2)X+4 has equal roots​

Answer 1

Step-by-step explanation:

Equal roots Discriminant → b² - 4ac = 0

Then, in x² + 2(k+1)x + x²

a = 1 b = 2(k+1) c = k²

We substitute these values,

0 = (2(k+1))² - 4(1)(k²)

0 = 4(k+1)² - 4k²

0 = 4(k²+2k+1) - 4k²

0 = 4k² + 8k + 4 - 4k²

(cancelling 4k² and -4k²)

0 = 8k + 4

8k = -4

k = -4/8

k = -1/2

Hence the value of k = -1/2

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