The quadratic equation x²-4root3x-3=0 has how many roots
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0
Answer:
2
Step-by-step explanation:
Discrimant is = b²-4ac
Here D= 60>0
So, It has two real roots
Answered by
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Polynomial in variable x :
p(x)=x2−4 3–√x+3
Given,
α,β are the zeroes of p(x) .
p(x) is a quadratic polynomial with a degree 2
From the properties of a quadratic polynomial, we know the relation between quotients (those constants except for variables) and zeroes — α,β .
In p(x) , a=1|b=−43–√|c=3
sum of Zeroes:-
α+β=−ba→
−(−43√)1
43–√
α+β=43–√ ——————— Eq.1
Product of Zeroes :-
αβ=ca
31
αβ=3 —————Eq.2
(α+β)−(αβ)=?
43–√−3
(α+β)−(αβ)=43–√− 3≈(4×1.732)−3
≈6.92−3
≈3.92
∴(α+β)−(αβ)=43–√−3≈3.92 (approx.)
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