Question

the quadratic equation x²+4x-7=0 has​

Answer 1

Answer:

The quadratic equation x²+4x-7=0 has two different real roots . These roots are -2+√11 and -2-√11.

Step-by-step explanation:

x²+4x-7=0

a=1, b=4, c= -7

D= b²- 4ac

= 4² - 4*1*(-7)

= 16 + 28

= 44

D > 0, So the given quadratic equation will have two different real roots.

x= -b + √D/ 2 a

= -4 + √44 / 2*1

= -4 + 2√11 / 2

= 2(-2 + √11)/ 2

= -2 + √11

The roots of the given quadratic equation are

-2+√11 , -2-√11

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