Question

The quadratic equation x2

– 6x + 9 = 0 has two distinct real roots. true or false​

Answer 1

Answer:

False

Step-by-step explanation:

x2-6x+9=0

a=1,b=-6,c=9

Discriminant=b2-4ac

=(-6)2-4×1×9

=36-36

=0

It has two real roots

Answer 2

Answer:

false

Step-by-step explanation:

$x^{2} -6x+9=0$

$x^{2} -3x-3x+9=0$

x(x-3)-3(x-3)=0

$(x-3)^{2} =0$

x-3=0

x=3 is the only root