Question

The quadratic equation x2-6x+a=0 and x2-cx+6=0 have one root in common . the other roots are integer in the ratio 4:3 respectively. the common root is

Answer 1

this is ur required result

Answer 2

Common root = 2

Step-by-step explanation:

x² - 6x  + a = 0

Let say roots are  p  & 4q

x² - cx + 6 = 0

Let say roots are  p  & 3q

p is the common root

p*4q  = a

p*3q = 6

=> 4/3 = a/6

=> a = 8

=> x² - 6x + 8 = 0

=> (x - 4)(x - 2) = 0

=> x = 2 or 4

if 4q = 2  then 3q is not integer

=> 4q = 4 and 3q = 3

and p = 2

Common root = 2

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