Question

the quadratic equation x²–x–2=0 has roots which are​

Answer 1

Answer:

Hey!! Ur answer:

${x}^{2} - x - 2 = 0 \\ = {x}^{2} + x - 2x - 2 \\ = x(x + 1) - 2( x+ 1) \\ = (x - 2)(x + 1) \\ \\ \\ > x - 2 = 0 \\ = > x = 2 \\ > x + 1 = 0 \\ = > x = ( - 1)\\ the \: roots \: of \: this \: quadratic \\ \: equation \: are \: \\ 2 \: and \: (- 1)$

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given that,

x^2−x−2=0

Comparing with ax^2+bx+c=0, we get,

a=1,b=−1 and c=−2

We know that, D=b^2−4ac

∴ D=(−1)^2−4(1)(−2)=1+8=9

⇒D>0

Since, the discriminant is positive, the given equation will have two distinct real roots.

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