Question

the quadratic equation2x²+kx+2 = 0 has distinct
real roots if k is​

Answer 1

Answer:

k^2-4*2*2>0

k^2-16>0

k^2>16

k>√16

k>+-4

Answer 2

Answer:

The given equation is 2x²+Kx+2=0

since the roots are real and distinct

since, Disc. > 0

(-k)² - 4*(2)*(2)>0

k² - 16 > 0

k² > 16

k > √16 or k > -√16

i.e. k > 4 or k > -4

i.e k may have any value greater than 4 or any less than -4

i.e. k €(- infinite ,-4) U (4, infinite)