The quadratic equations x2 - 6x + a=0 and x2 - cx + 6 = 0 have one root in common. The other roots of the first and second equations are integers in the ratio 4:3. Then the common root is
[AIEEE-2008]
(A)1
(B)4
(C)3
(D) 2
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Answer:it's d . a= 2
Let the common root of the given quadratic equation be α the other of equation x2 –6x + a = 0 be β and for x2 – cx + 6 = 0 be γ.
For x2 –6x + a = 0
(refer image 1)
For x2 – cx + 6 = 0
(refer image 1)
On dividing (2) by (3), we get
(refer image 2)
So, from (2), αβ = 8
and from (1) α + β = 6
⇒ β = 6 – α
⇒ α (6 – α) = 8
⇒ 6α – α2 = 8
⇒ α2 – 6α + 8 = 0
⇒ α2 – 4α – 2α + 8 = 0
⇒ (α – 4) (α – 2) = 0
⇒ α = 2, 4
So, α can be 2 or 4,
Hence the common root is 2.
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