Question

The quadratic function with zeros at -5± √6 and passes through the point (-1,20)

How would I do this?

Answer 1

Answer:

Step-by-step explanation:

Let us consider the following quadratic function: f(x) = x2 -6x -20

The solutions of the quadratic equation x2 -6x -20 = 0 correspond to the zeros or the roots of the function f(x) = x2 -6x -20.  

These are the points where the graph of f(x) cuts the x-axis. The graph cuts the Y-axis at -20.

                                     The Discriminant and Roots of the Quadratic Equation x2 -6x -20 = 0

The standard form of a quadratic equation is ax2 + bx + c = 0, where "a" does not equal 0. Note that if a = 0, the x2 term would disappear and the equation would be linear.

Looking at the given quadratic function  a = 1, b = -6, c = -20.  

The discriminant D = b2 - 4ac = -62 - 4 * (1) * (-20) = 116.0

The roots of the equation are  (-b - √D)/2a and (-b + √D)/2a  

= (-(-6) - √116.0)/(2(1)) and (-(-6) + √116.0)/(2(1))

= -2.385 and 8.385