The quadratic polynomial ax² + bx + c, a≠0 is represented by this graph then a is
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This graph shows that there are two zeroes of this polynomial.
You can write it in the following way
x^2+(b/a)x+c/a
If alpha and beta are two zeroes, then
alpha+beta=-(b/a) and alpha×beta=c/a
I don't think 2 can be related in any of the above to find a
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Since, both the zeroes lie on the postage x axis ( in 1st quadrant).... We many conclude that the zeroes pf polynomial are positive and more than zero (from origin) , so the value of a will be any natural number.
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