Question

The quadratic polynomial having sum of the zeroes of 8 and the product of zeroes 12 is___ *​

Answer 1

Answer :

k [x^2 - (Alpha +beta )x+ alpha ×beta ]

= k [ x^2 - (8)x + 12 ]

= x^2 - 8x +12 his is required answer

I wish it helps you

Answer 2

Answer : x2-8x+12

Explanation:

In the question, they gave the sum of the zeroes is 8 and product of zeroes is 12.

Let us consider the equation to be ax2 + bx + c = 0. And the roots be m, n.

So, from the given data m + n = 8 and m*n = 12.

The required equation is, x2 - (m+n) x + (m*n) = 0

I.e. x2 - 8x + 12 = 0

{
Further explanation / detailed derivation:
we know
m+n = (-b/a),
m*n = (c/a)

So, (b/a) = -8 ; (c/a) = 12 -------> ⓛ

Let us now simplify the considered equation as,
x2 + (b/a)x + (c/a) = 0

Now substitute the values from ⓛ

The equation becomes, x2 + (-8)x + 12 = 0
i.e; x2 - 8x + 12.
}