Question

the quadratic polynomial in x whose 0 are a,2a is​

Answer 1

Answer :-

$x^2 - 3ax + 2a^2$

Given :-

$\alpha = a$

$\beta = 2a$

To find :-

The required quadratic polynomial.

Solution:-

Let the zeroes of required polynomial be $\alpha\: and</p><p> \: \beta$

The required quadratic polynomial is given by :-

→$x^2 - (\alpha + \beta ) x + \alpha \beta$

→$x^2 -( a +2a) x + a \times 2a$

→$x^2 - 3ax + 2a^2$

The required quadratic polynomial is :-

$\mathbb\red{x^2 - 3ax + 2a^2}$

Thanks to $\textbf{@Durgapal Singh}$

$\text{Ex - Star leader}$

Answer 2

Explanation:-

Let zeroes of the quadratic polynomial be $\alpha$ and $\beta$.

As we know a quadratic polynomial has two zeroes whose value is given.

$\alpha = a$

$\beta = 2a$

Now,

• By using fromual of quadratic polynomial.

→$x^2 -(\alpha + \beta )x + \alpha \beta$

• Put the above value.

→$x^2 -(a +2a) x + a \times 2a$

→$x^2 -3ax + 2a^2$

Hence,

The quadratic polynomial will be $x^2 -3ax + 2a^2$.

• Zeroes of the quadratic polynomial is that value which when put in equation gives result 0.