Question

the quadratic polynomial whose sum and product of the zeroes are 21/8 and 5/16 respectively is_____​

Answer 1

Step-by-step explanation:

The quadratic polynomial is

${x}^{2} - \frac{21}{8} x + \frac{5}{16} = 0 \\ 16 {x}^{2} - 42x + 5 = 0$

Thank you

Answer 2

Answer:

16$x^{2}$ - 42x + 5

Step-by-step explanation:

Sum of zeroes = 21/8

Product of zeroes = 5/16

Let the quadratic polynomial be a$x^{2}$ + bx + c,

α + β = 21/8 = -b/a  

and  αβ = 5/16 = c/a

If a = 16 , b = -42 and c = 5

So,

16$x^{2}$ - 42x + 5

I hope this answer is helpful for you.