Question

the quadratic polynomial whose zeroes are 2 and 4 is

Answer 1

Answer:

${x}^{2} - (sum \: \: of \: \: roots \: )x + multiply \: \: of \: \: roots = 0 \\ \\ {x}^{2} - 6x + 8 = 0$

Answer 2

Answer:

x²-6x + 8

Step-by-step explanation:

Let zeroes be α and b.

Now, a+b = 2+4=6 =-b/a

ab=4.2=8=c/a

So... ax²-bx +c

= x²-6x + 8