Question

the quadratic polynomial whose zeroes are 2 and 5​

Answer 1

Step-by-step explanation:

x²+7x+10

x²+5x+2x+10

(x+2)(X+5)

here, x = 2 & 5

Answer 2

Answer:

Hey Mate!! Let me help you for this question....

Given:

Zeroes of some equation  is 2 & 5

To Find:

The unknown equation

Solution:

Let us consider the variable of the equation as 'x'

Now, if 2 & 5 are the zeroes then these values should satisfy the value of 'x' to get the answer as zero

=> x = 2     and       x = 5

=>  (x - 2) = 0 and  (x - 5) = 0

After multiplying these two eqautions....

=> (x - 2)(x - 5) = 0

=>  $x^{2} - 5x-2x+10=0$

Therefore our required equation is,  $x^{2} -7x+10 = 0$

Hope this answer helped you..........

Please mark me as Brainliest!!!!!