Question

the quadratic polynomial whose zeroes are 3/5 and 1/2 is​

Answer 1

Answer:

Let, a and b be the roots of quadratic polynomial where a=3/5 and b=1/2

now, a+b = 11/10

ab = 3/10

required polynomial is as

P(x)= x^2-(a+b)x+ab

P(x) = x^2-(11/10)x+3/10

P(x) = (10x^2-11x+3)/10

required polynomial is 10x^2-11x+3

Answer 2

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Answer:

10x^2 + 11x + 3

Step-by-step explanation:

(alpha + beta) = 3/5 + 1/2

= 11/10

(alpha × beta) = 3/5 × 1/2

=3/10

the equation becomes as

x^2 + 11/10x + 3/10

10x^2 + 11x + 3

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