Question

The quadratic polynomial whose zeroes are 3 and √2 is​

Answer 1

Answer:

The quadratic polynomial whose zeros are $3$ and $\sqrt{2}$ is

$p(x)=x^{2} -(3+\sqrt{2} )x+3\sqrt{2}$

Step-by-step explanation:

It can be found by considering the factors since the values are given.

That is $p(x)=(x-3)(x-\sqrt{2} )$

                   $=x^{2} -3x-\sqrt{2}x+3\sqrt{2}\\\\=x^{2} -(3+\sqrt{2} ) x+3\sqrt{2}$.

Hence the answer.

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