Question

the quadratic polynomial whose zeros are -3/4 and 5/6 is:​

Answer 1

Step-by-step explanation:

$\alpha = \frac{ - 3}{4} \\ \beta = \frac{5}{6} \\ equation = {x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ \: \: \: \: \: \: = {x}^{2} - ( \frac{ - 3}{4} + \frac{5}{6} ) x+ ( \frac{ - 3}{4} )( \frac{5}{6} ) \\ \: \: \: \: \: \: = {x}^{2} - ( \frac{ - 9 + 10}{12} )x - \frac{15}{24} \\ \: \: \: \: \: \: = {x}^{2} - \frac{1}{12} x - \frac{5}{8}$

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