Question

The quadratic polynomial whose zeros are 3/5 and -1/2 is

Answer 1

Answer:

10x^2 -x-3

Step-by-step explanation:

let a= 3/5 and  b= -1/2 are the zeroes of the polynomial.

The quadratic polynomial can be written as (x-3/5)(x+1/2)  =(5x-3)(2x+1)

=10x^2 -x- 3 =0

Answer 2

Solution :

Let, the zeroes are α = 3/5 and β = - 1/2

Then, the quadratic polynomial whose roots are α and β is

f (x) = (x - α) (x - β)

⇒ f (x) = (x - 3/5) {x - (- 1/2)}

⇒ f (x) = (x - 3/5) (x + 1/2)

⇒ f (x) = {(5x - 3) (2x + 1)}/(5 * 2)

⇒ f (x) = 1/10 * (10x² - x - 3)

∴ the required quadratic polynomial is

10x² - x - 3.