The quadratic polynomial, whose zeros are resp., 3 and -4 is
(a) x2+x-12 (b) x2-x-12 (c) x2-12x+1 (d) x2-12x-1
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Answer:
Option (a) x² + x -12, where k = 1
Step-by-step explanation:
Sum of the zeroes, S = 3 -4 = -1
Product of the zeroes, P = 3 × (-4) = -12
Required polynomial
= k( x² - Sx + P)
= x² + x -12, where k = 1
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