Question

The quadratic polynomial with -15 and -7 as the sum and one of the zeros what?

Answer 1

Given:

• Sum of zeroes of a quadratic polynomial is -15.
• One of its zero is (-7).

To Find:

• The quadratic polynomial.

Answer:

Here given that the sum of zeroes is (-15) and one of its zero is (-7).

Let us take another zero be ß .

Atq , ß + (-7) = -15 .

=> ß = 7 -15 .

Therefore ß = (-8).

Hence we found the two zeroes as -7 and -8 .

Here is a formula to find quadratic polynomial when zeroes are given:

$\large{\underline{\boxed{\red{\sf{\hookrightarrow p(x)=k[x^{2}-(\alpha+\beta)x+\alpha\beta]}}}}}$

where

• Alpha and Beta are zeroes .
• k is a constant.

Using above formula ,

=> p(x) = k[ x² - (-7-8)x+(-8×-7)].

=> p(x) = k[x² -(-15)x +56]

Hence p(x) = k[x²+15x+56].

Hence the required polynomial is k[x²+15x+56].

Answer 2

Given

•sum of zeroes of a quadratic polynomial is -15.

•one of its zero is (-7).

To find

•The quadratic polynomial.

Answer

Here gives than the sum of zeroes is (-15)and one of its zero is (-7)

Let us take another zero be B.

Atq, B +(-7)=-15

= >B = 7-15

therefore B=(-8)