Question

the quadratic polynomial x2 + kx -20 has p and q as it zeros such that p-q =9 what is the value of k

Answer 1

Answer:

the value of k is 1

Step-by-step explanation:

p(x)=x^2+kx-20

p and q are the zeroes

p-q=9

square on both side

(p-q)^2=9^2

p^2+q^2-2pq=81

(p+q)^-2pq-2pq=81

(p+q)^2-4pq=81

sum of the zeroes=p+q=-b/a=-k/1=-k

product of the zeroes=p×q=c/a=-20

(p+q)^2-4pq=81

(-k)^2-4(-20)=81

k^2+80=81

k^2=81-80

k^2=1

k=root1

k=1

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