Question

the quadrative polynomials having zeroes 1 and-2​

Answer 1

Answer:

${x}^{2} - x - 2$

Answer 2

Step-by-step explanation:

zeroes of the polynomial = 1 & -2

sum of it's zeroes = 1+(-2) = -1 = -b/a..............(1)

product pf it's zeroes = 1×(-2) = -2 = -c/a......(2)

from (1) & (2) we get

b = -1

a = 1

c = -2

so polynomial = ax²+bx+c

=1(x²) + (-1)x + (-2)

=x²-x-2

Hence, polynomial = x²-x-2