Math, asked by anudarling6464, 3 months ago

The quadric equation whose roots are (4 + sqrt(7))/2 and is * (4 - sqrt(7))/2 a.4x^ 2 +16x+9=0 b. 4x ^ 2 - 16x - 9 = 0 C. 4x ^ 2 - 16x + 9 = 0 [ d. 4x ^ 2 + 16x - 9 = 0 ]​

Answers

Answered by rkcomp31
3

Answer:

4x²-16x+9=0

option(c)

Step-by-step explanation:

Roots are|

(4+√7)/2 and (4-√7)/2

so the eqn is

x²-( sum of roots)x + product of roots=0

x²-{ (4+√7)/2 + (4-√7)/2 } +(4+√7)/2* (4-√7)/2

x²-(8)/2 *x+(16-7)/4=0

x²-4x+9/4=0

4x²-16x+9=0

option(c)

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