Math, asked by lrcj0806, 10 months ago

The quadrilateral shown is a rhombus. If AB = 17 and AE = 8, what is the measure of BE? A) 11 B) 13 C) 15 D) 19

Answers

Answered by bhagyashreechowdhury
4

If AB = 17 and AE = 8, then the measure of BE is option (C): 15.

Step-by-step explanation:

Referring to the figure attached below, we have

ABCD is a rhombus with the diagonals intersecting at E

Each side of a rhombus, AB = BC = CD = DA = 17  

The measure of AE = 8

We know that the diagonals of a rhombus bisect each other at right angles.

∠AEB = ∠BEC = ∠CED = ∠DEA = 90°

Now, considering ∆ AEB and applying Pythagoras theorem, we get

AB² = AE² + BE²

⇒ BE = √[AB² – AE²]

⇒ BE = √[17² – 8²]

⇒ BE = √[225]

BE = 15

Thus, the measure of the BE is 15.

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