Math, asked by ashishkushwaha5, 2 days ago

The quadrilateral whose diagonals measure 48 m and 32m respectively and bisect each othen at right angles. Find its area and perimeter.​

Answers

Answered by mohitguptaiitk177
2

Answer:

Area=768m²    Perimeter = 115.38m

Step-by-step explanation:

As in the quadrilateral, diagonals bisect each other at 90°

Therefore, it is a rhombus.

We also know that area of a rhombus = 1/2 * d1 * d2

   =>                                               Area = 1/2*48m*32m = 768m²

also side length of rhombus = √( (d1/2)² + (d2/2)² )

                                             a = √( (48/2)² + (32/2)² )

                                                = 28.844m

Therefore,              Perimeter = 4 * a = 115.38m

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